A Bidimensional Hilbert-like Curve defined with {X4(...),Y4(...)} -iteration 4- [Une courbe bidimensionnelle du type Hilbert définie avec {X4(...),Y4(...)} -itération 4-].





The bidimensional Hilbert Curves:

Let's C1(T) being a parametric curve defined by means of 2 real functions of T (T [0,1]) X1(T) [0,1] and Y1(T) [0,1] such as :
                    X1(T=0)=0 Y1(T=0)=0 (lower left corner)
                    X1(T=1)=1 Y1(T=1)=0 (lower right corner)


Then one defines a sequence of curves Ci(T) (i >= 1) as follows :
                    Ci(T) = {Xi(T),Yi(T)}  [0,1]x[0,1] --> Ci+1(T) = {Xi+1(T),Yi+1(T)}  [0,1]x[0,1]

                    if T  [0,1/4[:
                              Xi+1(T) =   Yi(4T-0)
                              Yi+1(T) =   Xi(4T-0)
                                                   Transformation 1
                    if T  [1/4,2/4[:
                              Xi+1(T) =   Xi(4T-1)
                              Yi+1(T) = 1+Yi(4T-1)
                                                   Transformation 2
                    if T  [2/4,3/4[:
                              Xi+1(T) = 1+Xi(4T-2)
                              Yi+1(T) = 1+Yi(4T-2)
                                                   Transformation 3
                    if T  [3/4,1]:
                              Xi+1(T) = 2-Yi(4T-3)
                              Yi+1(T) = 1-Xi(4T-3)
                                                   Transformation 4

Please note that 4=2d where d=2 is the space dimension.



See a special C1(T) curve in order to understand the geometrical meaning of the 4 transformations and of their order .


Here are the five first bidimensional Hilbert curves with an increasing number of iterations :

[See the used color set to display the parameter T]


Here are some examples of Hilbert-like bidimensional curves using different generating curves :


















The tridimensional Hilbert Curves:

Let's C1(T) being a parametric curve defined by means of 3 real functions of T (T [0,1]) X1(T) [0,1], Y1(T) [0,1] and Z1(T) [0,1] such as :
                    X1(T=0)=0 Y1(T=0)=0 Z1(T=0)=0 (lower left foreground corner)
                    X1(T=1)=1 Y1(T=1)=0 Z1(T=1)=0 (lower right foreground corner)


Then one defines a sequence of curves Ci(T) (i >= 1) as follows :
                    Ci(T) = {Xi(T),Yi(T),Zi(T)}  [0,1]x[0,1]x[0,1] --> Ci+1(T) = {Xi+1(T),Yi+1(T),Zi+1(T)}  [0,1]x[0,1]x[0,1]

                    if T  [0,1/8[:
                              Xi+1(T) =   Xi(8T-0)
                              Yi+1(T) =   Zi(8T-0)
                              Zi+1(T) =   Yi(8T-0)
                                                   Transformation 1
                    if T  [1/8,2/8[:
                              Xi+1(T) =   Zi(8T-1)
                              Yi+1(T) = 1+Yi(8T-1)
                              Zi+1(T) =   Xi(8T-1)
                                                   Transformation 2
                    if T  [2/8,3/8[:
                              Xi+1(T) = 1+Xi(8T-2)
                              Yi+1(T) = 1+Yi(8T-2)
                              Zi+1(T) =   Zi(8T-2)
                                                   Transformation 3
                    if T  [3/8,4/8[:
                              Xi+1(T) = 1+Zi(8T-3)
                              Yi+1(T) = 1-Xi(8T-3)
                              Zi+1(T) = 1-Yi(8T-3)
                                                   Transformation 4
                    if T  [4/8,5/8[:
                              Xi+1(T) = 2-Zi(8T-4)
                              Yi+1(T) = 1-Xi(8T-4)
                              Zi+1(T) = 1+Yi(8T-4)
                                                   Transformation 5
                    if T  [5/8,6/8[:
                              Xi+1(T) = 1+Xi(8T-5)
                              Yi+1(T) = 1+Yi(8T-5)
                              Zi+1(T) = 1+Zi(8T-5)
                                                   Transformation 6
                    if T  [6/8,7/8[:
                              Xi+1(T) = 1-Zi(8T-6)
                              Yi+1(T) = 1+Yi(8T-6)
                              Zi+1(T) = 2-Xi(8T-6)
                                                   Transformation 7
                    if T  [7/8,1]:
                              Xi+1(T) =   Xi(8T-7)
                              Yi+1(T) = 1-Zi(8T-7)
                              Zi+1(T) = 2-Yi(8T-7)
                                                   Transformation 8

Please note that 8=2d where d=3 is the space dimension.



See a special C1(T) curve in order to understand the geometrical meaning of the 8 transformations and of their order .


Here are the four first tridimensional Hilbert curves with an increasing number of iterations :

[See the used color set to display the parameter T]


Here are some examples of Hilbert-like tridimensional curves using different generating curves and in particular "open" knots :









[More information about Peano Curves and Infinite Knots -in english/en anglais-]
[Plus d'informations à propos des Courbes de Peano et des Nœuds Infinis -en français/in french-]














See various Bidimensional Hilbert and Peano Curves (possibly including this one):




See Bidimensional Hilbert Curves, their nodes being "loaded" with some data (related to prime numbers, real number digits,...):

 
See the used color set to display the parameter T.  
See the used color set to display the pi digits.  







See various Tridimensional Hilbert and Peano Curves (possibly including this one):




See Tridimensional Hilbert Curves, their nodes being "loaded" with some data (related to prime numbers, real number digits,...):

 
See the used color set to display the parameter T.  
See the used color set to display the pi digits.


(CMAP28 WWW site: this page was created on 04/29/2022 and last updated on 07/04/2023 12:13:39 -CEST-)



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